3.26.27 \(\int \frac {(a+b x)^{4/3}}{(c+d x)^{4/3} (e+f x)^3} \, dx\)

Optimal. Leaf size=434 \[ \frac {3 d (a+b x)^{7/3}}{\sqrt [3]{c+d x} (e+f x)^2 (b c-a d) (d e-c f)}-\frac {(a+b x)^{4/3} (c+d x)^{2/3} (-7 a d f+b c f+6 b d e)}{2 (e+f x)^2 (b c-a d) (d e-c f)^2}+\frac {2 \sqrt [3]{a+b x} (c+d x)^{2/3} (-7 a d f+b c f+6 b d e)}{3 (e+f x) (d e-c f)^3}-\frac {(b c-a d) \log (e+f x) (-7 a d f+b c f+6 b d e)}{9 (b e-a f)^{2/3} (d e-c f)^{10/3}}+\frac {(b c-a d) (-7 a d f+b c f+6 b d e) \log \left (\frac {\sqrt [3]{c+d x} \sqrt [3]{b e-a f}}{\sqrt [3]{d e-c f}}-\sqrt [3]{a+b x}\right )}{3 (b e-a f)^{2/3} (d e-c f)^{10/3}}+\frac {2 (b c-a d) (-7 a d f+b c f+6 b d e) \tan ^{-1}\left (\frac {2 \sqrt [3]{c+d x} \sqrt [3]{b e-a f}}{\sqrt {3} \sqrt [3]{a+b x} \sqrt [3]{d e-c f}}+\frac {1}{\sqrt {3}}\right )}{3 \sqrt {3} (b e-a f)^{2/3} (d e-c f)^{10/3}} \]

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Rubi [A]  time = 0.30, antiderivative size = 434, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {96, 94, 91} \begin {gather*} \frac {3 d (a+b x)^{7/3}}{\sqrt [3]{c+d x} (e+f x)^2 (b c-a d) (d e-c f)}-\frac {(a+b x)^{4/3} (c+d x)^{2/3} (-7 a d f+b c f+6 b d e)}{2 (e+f x)^2 (b c-a d) (d e-c f)^2}+\frac {2 \sqrt [3]{a+b x} (c+d x)^{2/3} (-7 a d f+b c f+6 b d e)}{3 (e+f x) (d e-c f)^3}-\frac {(b c-a d) \log (e+f x) (-7 a d f+b c f+6 b d e)}{9 (b e-a f)^{2/3} (d e-c f)^{10/3}}+\frac {(b c-a d) (-7 a d f+b c f+6 b d e) \log \left (\frac {\sqrt [3]{c+d x} \sqrt [3]{b e-a f}}{\sqrt [3]{d e-c f}}-\sqrt [3]{a+b x}\right )}{3 (b e-a f)^{2/3} (d e-c f)^{10/3}}+\frac {2 (b c-a d) (-7 a d f+b c f+6 b d e) \tan ^{-1}\left (\frac {2 \sqrt [3]{c+d x} \sqrt [3]{b e-a f}}{\sqrt {3} \sqrt [3]{a+b x} \sqrt [3]{d e-c f}}+\frac {1}{\sqrt {3}}\right )}{3 \sqrt {3} (b e-a f)^{2/3} (d e-c f)^{10/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^(4/3)/((c + d*x)^(4/3)*(e + f*x)^3),x]

[Out]

(3*d*(a + b*x)^(7/3))/((b*c - a*d)*(d*e - c*f)*(c + d*x)^(1/3)*(e + f*x)^2) - ((6*b*d*e + b*c*f - 7*a*d*f)*(a
+ b*x)^(4/3)*(c + d*x)^(2/3))/(2*(b*c - a*d)*(d*e - c*f)^2*(e + f*x)^2) + (2*(6*b*d*e + b*c*f - 7*a*d*f)*(a +
b*x)^(1/3)*(c + d*x)^(2/3))/(3*(d*e - c*f)^3*(e + f*x)) + (2*(b*c - a*d)*(6*b*d*e + b*c*f - 7*a*d*f)*ArcTan[1/
Sqrt[3] + (2*(b*e - a*f)^(1/3)*(c + d*x)^(1/3))/(Sqrt[3]*(d*e - c*f)^(1/3)*(a + b*x)^(1/3))])/(3*Sqrt[3]*(b*e
- a*f)^(2/3)*(d*e - c*f)^(10/3)) - ((b*c - a*d)*(6*b*d*e + b*c*f - 7*a*d*f)*Log[e + f*x])/(9*(b*e - a*f)^(2/3)
*(d*e - c*f)^(10/3)) + ((b*c - a*d)*(6*b*d*e + b*c*f - 7*a*d*f)*Log[-(a + b*x)^(1/3) + ((b*e - a*f)^(1/3)*(c +
 d*x)^(1/3))/(d*e - c*f)^(1/3)])/(3*(b*e - a*f)^(2/3)*(d*e - c*f)^(10/3))

Rule 91

Int[1/(((a_.) + (b_.)*(x_))^(1/3)*((c_.) + (d_.)*(x_))^(2/3)*((e_.) + (f_.)*(x_))), x_Symbol] :> With[{q = Rt[
(d*e - c*f)/(b*e - a*f), 3]}, -Simp[(Sqrt[3]*q*ArcTan[1/Sqrt[3] + (2*q*(a + b*x)^(1/3))/(Sqrt[3]*(c + d*x)^(1/
3))])/(d*e - c*f), x] + (Simp[(q*Log[e + f*x])/(2*(d*e - c*f)), x] - Simp[(3*q*Log[q*(a + b*x)^(1/3) - (c + d*
x)^(1/3)])/(2*(d*e - c*f)), x])] /; FreeQ[{a, b, c, d, e, f}, x]

Rule 94

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/((m + 1)*(b*e - a*f)), x] - Dist[(n*(d*e - c*f))/((m + 1)*(b*e - a*
f)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] &&  !(SumSimplerQ[p, 1] &&  !SumSimplerQ[m, 1])

Rule 96

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
 b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[(a*d*f*(m + 1)
 + b*c*f*(n + 1) + b*d*e*(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*
x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && EqQ[Simplify[m + n + p + 3], 0] && (LtQ[m, -1] || Sum
SimplerQ[m, 1])

Rubi steps

\begin {align*} \int \frac {(a+b x)^{4/3}}{(c+d x)^{4/3} (e+f x)^3} \, dx &=\frac {3 d (a+b x)^{7/3}}{(b c-a d) (d e-c f) \sqrt [3]{c+d x} (e+f x)^2}-\frac {(6 b d e+b c f-7 a d f) \int \frac {(a+b x)^{4/3}}{\sqrt [3]{c+d x} (e+f x)^3} \, dx}{(b c-a d) (d e-c f)}\\ &=\frac {3 d (a+b x)^{7/3}}{(b c-a d) (d e-c f) \sqrt [3]{c+d x} (e+f x)^2}-\frac {(6 b d e+b c f-7 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{2 (b c-a d) (d e-c f)^2 (e+f x)^2}+\frac {(2 (6 b d e+b c f-7 a d f)) \int \frac {\sqrt [3]{a+b x}}{\sqrt [3]{c+d x} (e+f x)^2} \, dx}{3 (d e-c f)^2}\\ &=\frac {3 d (a+b x)^{7/3}}{(b c-a d) (d e-c f) \sqrt [3]{c+d x} (e+f x)^2}-\frac {(6 b d e+b c f-7 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{2 (b c-a d) (d e-c f)^2 (e+f x)^2}+\frac {2 (6 b d e+b c f-7 a d f) \sqrt [3]{a+b x} (c+d x)^{2/3}}{3 (d e-c f)^3 (e+f x)}-\frac {(2 (b c-a d) (6 b d e+b c f-7 a d f)) \int \frac {1}{(a+b x)^{2/3} \sqrt [3]{c+d x} (e+f x)} \, dx}{9 (d e-c f)^3}\\ &=\frac {3 d (a+b x)^{7/3}}{(b c-a d) (d e-c f) \sqrt [3]{c+d x} (e+f x)^2}-\frac {(6 b d e+b c f-7 a d f) (a+b x)^{4/3} (c+d x)^{2/3}}{2 (b c-a d) (d e-c f)^2 (e+f x)^2}+\frac {2 (6 b d e+b c f-7 a d f) \sqrt [3]{a+b x} (c+d x)^{2/3}}{3 (d e-c f)^3 (e+f x)}+\frac {2 (b c-a d) (6 b d e+b c f-7 a d f) \tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [3]{b e-a f} \sqrt [3]{c+d x}}{\sqrt {3} \sqrt [3]{d e-c f} \sqrt [3]{a+b x}}\right )}{3 \sqrt {3} (b e-a f)^{2/3} (d e-c f)^{10/3}}-\frac {(b c-a d) (6 b d e+b c f-7 a d f) \log (e+f x)}{9 (b e-a f)^{2/3} (d e-c f)^{10/3}}+\frac {(b c-a d) (6 b d e+b c f-7 a d f) \log \left (-\sqrt [3]{a+b x}+\frac {\sqrt [3]{b e-a f} \sqrt [3]{c+d x}}{\sqrt [3]{d e-c f}}\right )}{3 (b e-a f)^{2/3} (d e-c f)^{10/3}}\\ \end {align*}

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Mathematica [C]  time = 0.43, size = 214, normalized size = 0.49 \begin {gather*} \frac {\frac {\sqrt [3]{a+b x} (-7 a d f+b c f+6 b d e) \left (3 (a+b x) (c+d x) (b e-a f) (d e-c f)-4 (e+f x) (b c-a d) \left ((c+d x) (b e-a f)-(e+f x) (b c-a d) \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )\right )\right )}{3 (b e-a f) (d e-c f)^2}-6 d (a+b x)^{7/3}}{2 \sqrt [3]{c+d x} (e+f x)^2 (b c-a d) (c f-d e)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^(4/3)/((c + d*x)^(4/3)*(e + f*x)^3),x]

[Out]

(-6*d*(a + b*x)^(7/3) + ((6*b*d*e + b*c*f - 7*a*d*f)*(a + b*x)^(1/3)*(3*(b*e - a*f)*(d*e - c*f)*(a + b*x)*(c +
 d*x) - 4*(b*c - a*d)*(e + f*x)*((b*e - a*f)*(c + d*x) - (b*c - a*d)*(e + f*x)*Hypergeometric2F1[1/3, 1, 4/3,
((d*e - c*f)*(a + b*x))/((b*e - a*f)*(c + d*x))])))/(3*(b*e - a*f)*(d*e - c*f)^2))/(2*(b*c - a*d)*(-(d*e) + c*
f)*(c + d*x)^(1/3)*(e + f*x)^2)

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IntegrateAlgebraic [B]  time = 73.78, size = 1307, normalized size = 3.01 \begin {gather*} -\frac {\sqrt [3]{d} \sqrt [3]{a+b x} \left (\sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c+d x}+\sqrt [3]{c f-d e} \sqrt [3]{a d+b x d}\right ) \left (d^{2/3} (b e-a f)^{2/3} (c+d x)^{2/3}-\sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c f-d e} \sqrt [3]{a d+b x d} \sqrt [3]{c+d x}+(c f-d e)^{2/3} (a d+b x d)^{2/3}\right ) \left (-\frac {\sqrt [3]{-b c+a d+b (c+d x)} \left (18 a e^2 d^{11/3}-18 b c e^2 d^{8/3}-36 a c e f d^{8/3}-6 b e^2 (c+d x) d^{8/3}+49 a e f (c+d x) d^{8/3}+18 a c^2 f^2 d^{5/3}+28 a f^2 (c+d x)^2 d^{5/3}-3 b e f (c+d x)^2 d^{5/3}+36 b c^2 e f d^{5/3}-49 a c f^2 (c+d x) d^{5/3}-37 b c e f (c+d x) d^{5/3}-18 b c^3 f^2 d^{2/3}-25 b c f^2 (c+d x)^2 d^{2/3}+43 b c^2 f^2 (c+d x) d^{2/3}\right )}{6 (d e-c f)^3 \sqrt [3]{c+d x} (d e-c f+f (c+d x))^2}+\frac {2 \left (7 \sqrt {3} d^2 f^3 a^4-8 \sqrt {3} b c d f^3 a^3-20 \sqrt {3} b d^2 e f^2 a^3+\sqrt {3} b^2 c^2 f^3 a^2+22 \sqrt {3} b^2 c d e f^2 a^2+19 \sqrt {3} b^2 d^2 e^2 f a^2-6 \sqrt {3} b^3 d^2 e^3 a-2 \sqrt {3} b^3 c^2 e f^2 a-20 \sqrt {3} b^3 c d e^2 f a+6 \sqrt {3} b^4 c d e^3+\sqrt {3} b^4 c^2 e^2 f\right ) \tan ^{-1}\left (\frac {\sqrt {3} \sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c+d x}}{\sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c+d x}-2 \sqrt [3]{c f-d e} \sqrt [3]{-b c+a d+b (c+d x)}}\right )}{9 (b e-a f)^{8/3} (c f-d e)^{10/3}}+\frac {2 \left (7 d^2 f^3 a^4-8 b c d f^3 a^3-20 b d^2 e f^2 a^3+b^2 c^2 f^3 a^2+22 b^2 c d e f^2 a^2+19 b^2 d^2 e^2 f a^2-6 b^3 d^2 e^3 a-2 b^3 c^2 e f^2 a-20 b^3 c d e^2 f a+6 b^4 c d e^3+b^4 c^2 e^2 f\right ) \log \left (\sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c+d x}+\sqrt [3]{c f-d e} \sqrt [3]{-b c+a d+b (c+d x)}\right )}{9 (b e-a f)^{8/3} (c f-d e)^{10/3}}+\frac {\left (-7 d^2 f^3 a^4+8 b c d f^3 a^3+20 b d^2 e f^2 a^3-b^2 c^2 f^3 a^2-22 b^2 c d e f^2 a^2-19 b^2 d^2 e^2 f a^2+6 b^3 d^2 e^3 a+2 b^3 c^2 e f^2 a+20 b^3 c d e^2 f a-6 b^4 c d e^3-b^4 c^2 e^2 f\right ) \log \left (d^{2/3} (b e-a f)^{2/3} (c+d x)^{2/3}-\sqrt [3]{d} \sqrt [3]{b e-a f} \sqrt [3]{c f-d e} \sqrt [3]{-b c+a d+b (c+d x)} \sqrt [3]{c+d x}+(c f-d e)^{2/3} (-b c+a d+b (c+d x))^{2/3}\right )}{9 (b e-a f)^{8/3} (c f-d e)^{10/3}}\right )}{(b c-a d) \sqrt [3]{a d+b x d} (-d e-d f x)} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(a + b*x)^(4/3)/((c + d*x)^(4/3)*(e + f*x)^3),x]

[Out]

-((d^(1/3)*(a + b*x)^(1/3)*(d^(1/3)*(b*e - a*f)^(1/3)*(c + d*x)^(1/3) + (-(d*e) + c*f)^(1/3)*(a*d + b*d*x)^(1/
3))*(d^(2/3)*(b*e - a*f)^(2/3)*(c + d*x)^(2/3) - d^(1/3)*(b*e - a*f)^(1/3)*(-(d*e) + c*f)^(1/3)*(c + d*x)^(1/3
)*(a*d + b*d*x)^(1/3) + (-(d*e) + c*f)^(2/3)*(a*d + b*d*x)^(2/3))*(-1/6*((-(b*c) + a*d + b*(c + d*x))^(1/3)*(-
18*b*c*d^(8/3)*e^2 + 18*a*d^(11/3)*e^2 + 36*b*c^2*d^(5/3)*e*f - 36*a*c*d^(8/3)*e*f - 18*b*c^3*d^(2/3)*f^2 + 18
*a*c^2*d^(5/3)*f^2 - 6*b*d^(8/3)*e^2*(c + d*x) - 37*b*c*d^(5/3)*e*f*(c + d*x) + 49*a*d^(8/3)*e*f*(c + d*x) + 4
3*b*c^2*d^(2/3)*f^2*(c + d*x) - 49*a*c*d^(5/3)*f^2*(c + d*x) - 3*b*d^(5/3)*e*f*(c + d*x)^2 - 25*b*c*d^(2/3)*f^
2*(c + d*x)^2 + 28*a*d^(5/3)*f^2*(c + d*x)^2))/((d*e - c*f)^3*(c + d*x)^(1/3)*(d*e - c*f + f*(c + d*x))^2) + (
2*(6*Sqrt[3]*b^4*c*d*e^3 - 6*Sqrt[3]*a*b^3*d^2*e^3 + Sqrt[3]*b^4*c^2*e^2*f - 20*Sqrt[3]*a*b^3*c*d*e^2*f + 19*S
qrt[3]*a^2*b^2*d^2*e^2*f - 2*Sqrt[3]*a*b^3*c^2*e*f^2 + 22*Sqrt[3]*a^2*b^2*c*d*e*f^2 - 20*Sqrt[3]*a^3*b*d^2*e*f
^2 + Sqrt[3]*a^2*b^2*c^2*f^3 - 8*Sqrt[3]*a^3*b*c*d*f^3 + 7*Sqrt[3]*a^4*d^2*f^3)*ArcTan[(Sqrt[3]*d^(1/3)*(b*e -
 a*f)^(1/3)*(c + d*x)^(1/3))/(d^(1/3)*(b*e - a*f)^(1/3)*(c + d*x)^(1/3) - 2*(-(d*e) + c*f)^(1/3)*(-(b*c) + a*d
 + b*(c + d*x))^(1/3))])/(9*(b*e - a*f)^(8/3)*(-(d*e) + c*f)^(10/3)) + (2*(6*b^4*c*d*e^3 - 6*a*b^3*d^2*e^3 + b
^4*c^2*e^2*f - 20*a*b^3*c*d*e^2*f + 19*a^2*b^2*d^2*e^2*f - 2*a*b^3*c^2*e*f^2 + 22*a^2*b^2*c*d*e*f^2 - 20*a^3*b
*d^2*e*f^2 + a^2*b^2*c^2*f^3 - 8*a^3*b*c*d*f^3 + 7*a^4*d^2*f^3)*Log[d^(1/3)*(b*e - a*f)^(1/3)*(c + d*x)^(1/3)
+ (-(d*e) + c*f)^(1/3)*(-(b*c) + a*d + b*(c + d*x))^(1/3)])/(9*(b*e - a*f)^(8/3)*(-(d*e) + c*f)^(10/3)) + ((-6
*b^4*c*d*e^3 + 6*a*b^3*d^2*e^3 - b^4*c^2*e^2*f + 20*a*b^3*c*d*e^2*f - 19*a^2*b^2*d^2*e^2*f + 2*a*b^3*c^2*e*f^2
 - 22*a^2*b^2*c*d*e*f^2 + 20*a^3*b*d^2*e*f^2 - a^2*b^2*c^2*f^3 + 8*a^3*b*c*d*f^3 - 7*a^4*d^2*f^3)*Log[d^(2/3)*
(b*e - a*f)^(2/3)*(c + d*x)^(2/3) - d^(1/3)*(b*e - a*f)^(1/3)*(-(d*e) + c*f)^(1/3)*(c + d*x)^(1/3)*(-(b*c) + a
*d + b*(c + d*x))^(1/3) + (-(d*e) + c*f)^(2/3)*(-(b*c) + a*d + b*(c + d*x))^(2/3)])/(9*(b*e - a*f)^(8/3)*(-(d*
e) + c*f)^(10/3))))/((b*c - a*d)*(a*d + b*d*x)^(1/3)*(-(d*e) - d*f*x)))

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fricas [B]  time = 4.60, size = 6825, normalized size = 15.73

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(4/3)/(d*x+c)^(4/3)/(f*x+e)^3,x, algorithm="fricas")

[Out]

[-1/18*(6*sqrt(1/3)*(6*(b^3*c^2*d^2 - a*b^2*c*d^3)*e^5 - (5*b^3*c^3*d + 8*a*b^2*c^2*d^2 - 13*a^2*b*c*d^3)*e^4*
f - (b^3*c^4 - 13*a*b^2*c^3*d + 5*a^2*b*c^2*d^2 + 7*a^3*c*d^3)*e^3*f^2 + (a*b^2*c^4 - 8*a^2*b*c^3*d + 7*a^3*c^
2*d^2)*e^2*f^3 + (6*(b^3*c*d^3 - a*b^2*d^4)*e^3*f^2 - (5*b^3*c^2*d^2 + 8*a*b^2*c*d^3 - 13*a^2*b*d^4)*e^2*f^3 -
 (b^3*c^3*d - 13*a*b^2*c^2*d^2 + 5*a^2*b*c*d^3 + 7*a^3*d^4)*e*f^4 + (a*b^2*c^3*d - 8*a^2*b*c^2*d^2 + 7*a^3*c*d
^3)*f^5)*x^3 + (12*(b^3*c*d^3 - a*b^2*d^4)*e^4*f - 2*(2*b^3*c^2*d^2 + 11*a*b^2*c*d^3 - 13*a^2*b*d^4)*e^3*f^2 -
 (7*b^3*c^3*d - 18*a*b^2*c^2*d^2 - 3*a^2*b*c*d^3 + 14*a^3*d^4)*e^2*f^3 - (b^3*c^4 - 15*a*b^2*c^3*d + 21*a^2*b*
c^2*d^2 - 7*a^3*c*d^3)*e*f^4 + (a*b^2*c^4 - 8*a^2*b*c^3*d + 7*a^3*c^2*d^2)*f^5)*x^2 + (6*(b^3*c*d^3 - a*b^2*d^
4)*e^5 + (7*b^3*c^2*d^2 - 20*a*b^2*c*d^3 + 13*a^2*b*d^4)*e^4*f - (11*b^3*c^3*d + 3*a*b^2*c^2*d^2 - 21*a^2*b*c*
d^3 + 7*a^3*d^4)*e^3*f^2 - (2*b^3*c^4 - 27*a*b^2*c^3*d + 18*a^2*b*c^2*d^2 + 7*a^3*c*d^3)*e^2*f^3 + 2*(a*b^2*c^
4 - 8*a^2*b*c^3*d + 7*a^3*c^2*d^2)*e*f^4)*x)*sqrt((-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c
 + a^2*d)*e*f^2)^(1/3)/(d*e - c*f))*log(-(3*a^2*c*f^2 + (b^2*c + 2*a*b*d)*e^2 - 2*(2*a*b*c + a^2*d)*e*f + 3*(-
b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)*(b*e - a*f)*(b*x + a)^(1/3)*(
d*x + c)^(2/3) + (3*b^2*d*e^2 - 2*(b^2*c + 2*a*b*d)*e*f + (2*a*b*c + a^2*d)*f^2)*x + 3*sqrt(1/3)*(2*(b*d*e^2 +
 a*c*f^2 - (b*c + a*d)*e*f)*(b*x + a)^(2/3)*(d*x + c)^(1/3) - (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*
f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(b*x + a)^(1/3)*(d*x + c)^(2/3) + (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*
d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)*(b*c*e - a*c*f + (b*d*e - a*d*f)*x))*sqrt((-b^2*d*e^3 + a^2*c*f^3 +
(b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)/(d*e - c*f)))/(f*x + e)) + 2*(-b^2*d*e^3 + a^2*c*f^3
+ (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(6*(b^2*c^2*d - a*b*c*d^2)*e^3 + (b^2*c^3 - 8*a*b*c
^2*d + 7*a^2*c*d^2)*e^2*f + (6*(b^2*c*d^2 - a*b*d^3)*e*f^2 + (b^2*c^2*d - 8*a*b*c*d^2 + 7*a^2*d^3)*f^3)*x^3 +
(12*(b^2*c*d^2 - a*b*d^3)*e^2*f + 2*(4*b^2*c^2*d - 11*a*b*c*d^2 + 7*a^2*d^3)*e*f^2 + (b^2*c^3 - 8*a*b*c^2*d +
7*a^2*c*d^2)*f^3)*x^2 + (6*(b^2*c*d^2 - a*b*d^3)*e^3 + (13*b^2*c^2*d - 20*a*b*c*d^2 + 7*a^2*d^3)*e^2*f + 2*(b^
2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*e*f^2)*x)*log(((b*d*e^2 + a*c*f^2 - (b*c + a*d)*e*f)*(b*x + a)^(2/3)*(d*x +
 c)^(1/3) + (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(b*x + a)^(1/3)
*(d*x + c)^(2/3) - (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)*(b*c*e -
 a*c*f + (b*d*e - a*d*f)*x))/(d*x + c)) - 4*(-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2
*d)*e*f^2)^(2/3)*(6*(b^2*c^2*d - a*b*c*d^2)*e^3 + (b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*e^2*f + (6*(b^2*c*d^2
- a*b*d^3)*e*f^2 + (b^2*c^2*d - 8*a*b*c*d^2 + 7*a^2*d^3)*f^3)*x^3 + (12*(b^2*c*d^2 - a*b*d^3)*e^2*f + 2*(4*b^2
*c^2*d - 11*a*b*c*d^2 + 7*a^2*d^3)*e*f^2 + (b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*f^3)*x^2 + (6*(b^2*c*d^2 - a*
b*d^3)*e^3 + (13*b^2*c^2*d - 20*a*b*c*d^2 + 7*a^2*d^3)*e^2*f + 2*(b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*e*f^2)*
x)*log(((b*d*e^2 + a*c*f^2 - (b*c + a*d)*e*f)*(b*x + a)^(1/3)*(d*x + c)^(2/3) - (-b^2*d*e^3 + a^2*c*f^3 + (b^2
*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(d*x + c))/(d*x + c)) + 3*(3*a^3*c^3*f^5 - 6*(4*b^3*c*d^2
 - 3*a*b^2*d^3)*e^5 + (20*b^3*c^2*d + 43*a*b^2*c*d^2 - 36*a^2*b*d^3)*e^4*f + 2*(2*b^3*c^3 - 28*a*b^2*c^2*d - 7
*a^2*b*c*d^2 + 9*a^3*d^3)*e^3*f^2 - (5*a*b^2*c^3 - 52*a^2*b*c^2*d + 5*a^3*c*d^2)*e^2*f^3 - 2*(a^2*b*c^3 + 8*a^
3*c^2*d)*e*f^4 - (3*b^3*d^3*e^4*f + 2*(11*b^3*c*d^2 - 17*a*b^2*d^3)*e^3*f^2 - (25*b^3*c^2*d + 16*a*b^2*c*d^2 -
 59*a^2*b*d^3)*e^2*f^3 + 2*(25*a*b^2*c^2*d - 17*a^2*b*c*d^2 - 14*a^3*d^3)*e*f^4 - (25*a^2*b*c^2*d - 28*a^3*c*d
^2)*f^5)*x^2 - (6*b^3*d^3*e^5 + (37*b^3*c*d^2 - 61*a*b^2*d^3)*e^4*f - 4*(9*b^3*c^2*d + 8*a*b^2*c*d^2 - 26*a^2*
b*d^3)*e^3*f^2 - (7*b^3*c^3 - 79*a*b^2*c^2*d + 47*a^2*b*c*d^2 + 49*a^3*d^3)*e^2*f^3 + 2*(7*a*b^2*c^3 - 25*a^2*
b*c^2*d + 21*a^3*c*d^2)*e*f^4 - 7*(a^2*b*c^3 - a^3*c^2*d)*f^5)*x)*(b*x + a)^(1/3)*(d*x + c)^(2/3))/(b^2*c*d^4*
e^8 + a^2*c^5*e^2*f^6 - 2*(2*b^2*c^2*d^3 + a*b*c*d^4)*e^7*f + (6*b^2*c^3*d^2 + 8*a*b*c^2*d^3 + a^2*c*d^4)*e^6*
f^2 - 4*(b^2*c^4*d + 3*a*b*c^3*d^2 + a^2*c^2*d^3)*e^5*f^3 + (b^2*c^5 + 8*a*b*c^4*d + 6*a^2*c^3*d^2)*e^4*f^4 -
2*(a*b*c^5 + 2*a^2*c^4*d)*e^3*f^5 + (b^2*d^5*e^6*f^2 + a^2*c^4*d*f^8 - 2*(2*b^2*c*d^4 + a*b*d^5)*e^5*f^3 + (6*
b^2*c^2*d^3 + 8*a*b*c*d^4 + a^2*d^5)*e^4*f^4 - 4*(b^2*c^3*d^2 + 3*a*b*c^2*d^3 + a^2*c*d^4)*e^3*f^5 + (b^2*c^4*
d + 8*a*b*c^3*d^2 + 6*a^2*c^2*d^3)*e^2*f^6 - 2*(a*b*c^4*d + 2*a^2*c^3*d^2)*e*f^7)*x^3 + (2*b^2*d^5*e^7*f + a^2
*c^5*f^8 - (7*b^2*c*d^4 + 4*a*b*d^5)*e^6*f^2 + 2*(4*b^2*c^2*d^3 + 7*a*b*c*d^4 + a^2*d^5)*e^5*f^3 - (2*b^2*c^3*
d^2 + 16*a*b*c^2*d^3 + 7*a^2*c*d^4)*e^4*f^4 - 2*(b^2*c^4*d - 2*a*b*c^3*d^2 - 4*a^2*c^2*d^3)*e^3*f^5 + (b^2*c^5
 + 4*a*b*c^4*d - 2*a^2*c^3*d^2)*e^2*f^6 - 2*(a*b*c^5 + a^2*c^4*d)*e*f^7)*x^2 + (b^2*d^5*e^8 + 2*a^2*c^5*e*f^7
- 2*(b^2*c*d^4 + a*b*d^5)*e^7*f - (2*b^2*c^2*d^3 - 4*a*b*c*d^4 - a^2*d^5)*e^6*f^2 + 2*(4*b^2*c^3*d^2 + 2*a*b*c
^2*d^3 - a^2*c*d^4)*e^5*f^3 - (7*b^2*c^4*d + 16*a*b*c^3*d^2 + 2*a^2*c^2*d^3)*e^4*f^4 + 2*(b^2*c^5 + 7*a*b*c^4*
d + 4*a^2*c^3*d^2)*e^3*f^5 - (4*a*b*c^5 + 7*a^2*c^4*d)*e^2*f^6)*x), -1/18*(12*sqrt(1/3)*(6*(b^3*c^2*d^2 - a*b^
2*c*d^3)*e^5 - (5*b^3*c^3*d + 8*a*b^2*c^2*d^2 - 13*a^2*b*c*d^3)*e^4*f - (b^3*c^4 - 13*a*b^2*c^3*d + 5*a^2*b*c^
2*d^2 + 7*a^3*c*d^3)*e^3*f^2 + (a*b^2*c^4 - 8*a^2*b*c^3*d + 7*a^3*c^2*d^2)*e^2*f^3 + (6*(b^3*c*d^3 - a*b^2*d^4
)*e^3*f^2 - (5*b^3*c^2*d^2 + 8*a*b^2*c*d^3 - 13*a^2*b*d^4)*e^2*f^3 - (b^3*c^3*d - 13*a*b^2*c^2*d^2 + 5*a^2*b*c
*d^3 + 7*a^3*d^4)*e*f^4 + (a*b^2*c^3*d - 8*a^2*b*c^2*d^2 + 7*a^3*c*d^3)*f^5)*x^3 + (12*(b^3*c*d^3 - a*b^2*d^4)
*e^4*f - 2*(2*b^3*c^2*d^2 + 11*a*b^2*c*d^3 - 13*a^2*b*d^4)*e^3*f^2 - (7*b^3*c^3*d - 18*a*b^2*c^2*d^2 - 3*a^2*b
*c*d^3 + 14*a^3*d^4)*e^2*f^3 - (b^3*c^4 - 15*a*b^2*c^3*d + 21*a^2*b*c^2*d^2 - 7*a^3*c*d^3)*e*f^4 + (a*b^2*c^4
- 8*a^2*b*c^3*d + 7*a^3*c^2*d^2)*f^5)*x^2 + (6*(b^3*c*d^3 - a*b^2*d^4)*e^5 + (7*b^3*c^2*d^2 - 20*a*b^2*c*d^3 +
 13*a^2*b*d^4)*e^4*f - (11*b^3*c^3*d + 3*a*b^2*c^2*d^2 - 21*a^2*b*c*d^3 + 7*a^3*d^4)*e^3*f^2 - (2*b^3*c^4 - 27
*a*b^2*c^3*d + 18*a^2*b*c^2*d^2 + 7*a^3*c*d^3)*e^2*f^3 + 2*(a*b^2*c^4 - 8*a^2*b*c^3*d + 7*a^3*c^2*d^2)*e*f^4)*
x)*sqrt(-(-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)/(d*e - c*f))*arcta
n(sqrt(1/3)*(2*(-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(b*x + a)^(1
/3)*(d*x + c)^(2/3) - (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(1/3)*(b*c*
e - a*c*f + (b*d*e - a*d*f)*x))*sqrt(-(-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*
f^2)^(1/3)/(d*e - c*f))/(b^2*c*e^2 - 2*a*b*c*e*f + a^2*c*f^2 + (b^2*d*e^2 - 2*a*b*d*e*f + a^2*d*f^2)*x)) + 2*(
-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(6*(b^2*c^2*d - a*b*c*d^2)*e
^3 + (b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*e^2*f + (6*(b^2*c*d^2 - a*b*d^3)*e*f^2 + (b^2*c^2*d - 8*a*b*c*d^2 +
 7*a^2*d^3)*f^3)*x^3 + (12*(b^2*c*d^2 - a*b*d^3)*e^2*f + 2*(4*b^2*c^2*d - 11*a*b*c*d^2 + 7*a^2*d^3)*e*f^2 + (b
^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*f^3)*x^2 + (6*(b^2*c*d^2 - a*b*d^3)*e^3 + (13*b^2*c^2*d - 20*a*b*c*d^2 + 7
*a^2*d^3)*e^2*f + 2*(b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*e*f^2)*x)*log(((b*d*e^2 + a*c*f^2 - (b*c + a*d)*e*f)
*(b*x + a)^(2/3)*(d*x + c)^(1/3) + (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2
)^(2/3)*(b*x + a)^(1/3)*(d*x + c)^(2/3) - (-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d
)*e*f^2)^(1/3)*(b*c*e - a*c*f + (b*d*e - a*d*f)*x))/(d*x + c)) - 4*(-b^2*d*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)
*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(6*(b^2*c^2*d - a*b*c*d^2)*e^3 + (b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)
*e^2*f + (6*(b^2*c*d^2 - a*b*d^3)*e*f^2 + (b^2*c^2*d - 8*a*b*c*d^2 + 7*a^2*d^3)*f^3)*x^3 + (12*(b^2*c*d^2 - a*
b*d^3)*e^2*f + 2*(4*b^2*c^2*d - 11*a*b*c*d^2 + 7*a^2*d^3)*e*f^2 + (b^2*c^3 - 8*a*b*c^2*d + 7*a^2*c*d^2)*f^3)*x
^2 + (6*(b^2*c*d^2 - a*b*d^3)*e^3 + (13*b^2*c^2*d - 20*a*b*c*d^2 + 7*a^2*d^3)*e^2*f + 2*(b^2*c^3 - 8*a*b*c^2*d
 + 7*a^2*c*d^2)*e*f^2)*x)*log(((b*d*e^2 + a*c*f^2 - (b*c + a*d)*e*f)*(b*x + a)^(1/3)*(d*x + c)^(2/3) - (-b^2*d
*e^3 + a^2*c*f^3 + (b^2*c + 2*a*b*d)*e^2*f - (2*a*b*c + a^2*d)*e*f^2)^(2/3)*(d*x + c))/(d*x + c)) + 3*(3*a^3*c
^3*f^5 - 6*(4*b^3*c*d^2 - 3*a*b^2*d^3)*e^5 + (20*b^3*c^2*d + 43*a*b^2*c*d^2 - 36*a^2*b*d^3)*e^4*f + 2*(2*b^3*c
^3 - 28*a*b^2*c^2*d - 7*a^2*b*c*d^2 + 9*a^3*d^3)*e^3*f^2 - (5*a*b^2*c^3 - 52*a^2*b*c^2*d + 5*a^3*c*d^2)*e^2*f^
3 - 2*(a^2*b*c^3 + 8*a^3*c^2*d)*e*f^4 - (3*b^3*d^3*e^4*f + 2*(11*b^3*c*d^2 - 17*a*b^2*d^3)*e^3*f^2 - (25*b^3*c
^2*d + 16*a*b^2*c*d^2 - 59*a^2*b*d^3)*e^2*f^3 + 2*(25*a*b^2*c^2*d - 17*a^2*b*c*d^2 - 14*a^3*d^3)*e*f^4 - (25*a
^2*b*c^2*d - 28*a^3*c*d^2)*f^5)*x^2 - (6*b^3*d^3*e^5 + (37*b^3*c*d^2 - 61*a*b^2*d^3)*e^4*f - 4*(9*b^3*c^2*d +
8*a*b^2*c*d^2 - 26*a^2*b*d^3)*e^3*f^2 - (7*b^3*c^3 - 79*a*b^2*c^2*d + 47*a^2*b*c*d^2 + 49*a^3*d^3)*e^2*f^3 + 2
*(7*a*b^2*c^3 - 25*a^2*b*c^2*d + 21*a^3*c*d^2)*e*f^4 - 7*(a^2*b*c^3 - a^3*c^2*d)*f^5)*x)*(b*x + a)^(1/3)*(d*x
+ c)^(2/3))/(b^2*c*d^4*e^8 + a^2*c^5*e^2*f^6 - 2*(2*b^2*c^2*d^3 + a*b*c*d^4)*e^7*f + (6*b^2*c^3*d^2 + 8*a*b*c^
2*d^3 + a^2*c*d^4)*e^6*f^2 - 4*(b^2*c^4*d + 3*a*b*c^3*d^2 + a^2*c^2*d^3)*e^5*f^3 + (b^2*c^5 + 8*a*b*c^4*d + 6*
a^2*c^3*d^2)*e^4*f^4 - 2*(a*b*c^5 + 2*a^2*c^4*d)*e^3*f^5 + (b^2*d^5*e^6*f^2 + a^2*c^4*d*f^8 - 2*(2*b^2*c*d^4 +
 a*b*d^5)*e^5*f^3 + (6*b^2*c^2*d^3 + 8*a*b*c*d^4 + a^2*d^5)*e^4*f^4 - 4*(b^2*c^3*d^2 + 3*a*b*c^2*d^3 + a^2*c*d
^4)*e^3*f^5 + (b^2*c^4*d + 8*a*b*c^3*d^2 + 6*a^2*c^2*d^3)*e^2*f^6 - 2*(a*b*c^4*d + 2*a^2*c^3*d^2)*e*f^7)*x^3 +
 (2*b^2*d^5*e^7*f + a^2*c^5*f^8 - (7*b^2*c*d^4 + 4*a*b*d^5)*e^6*f^2 + 2*(4*b^2*c^2*d^3 + 7*a*b*c*d^4 + a^2*d^5
)*e^5*f^3 - (2*b^2*c^3*d^2 + 16*a*b*c^2*d^3 + 7*a^2*c*d^4)*e^4*f^4 - 2*(b^2*c^4*d - 2*a*b*c^3*d^2 - 4*a^2*c^2*
d^3)*e^3*f^5 + (b^2*c^5 + 4*a*b*c^4*d - 2*a^2*c^3*d^2)*e^2*f^6 - 2*(a*b*c^5 + a^2*c^4*d)*e*f^7)*x^2 + (b^2*d^5
*e^8 + 2*a^2*c^5*e*f^7 - 2*(b^2*c*d^4 + a*b*d^5)*e^7*f - (2*b^2*c^2*d^3 - 4*a*b*c*d^4 - a^2*d^5)*e^6*f^2 + 2*(
4*b^2*c^3*d^2 + 2*a*b*c^2*d^3 - a^2*c*d^4)*e^5*f^3 - (7*b^2*c^4*d + 16*a*b*c^3*d^2 + 2*a^2*c^2*d^3)*e^4*f^4 +
2*(b^2*c^5 + 7*a*b*c^4*d + 4*a^2*c^3*d^2)*e^3*f^5 - (4*a*b*c^5 + 7*a^2*c^4*d)*e^2*f^6)*x)]

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {4}{3}}}{{\left (d x + c\right )}^{\frac {4}{3}} {\left (f x + e\right )}^{3}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(4/3)/(d*x+c)^(4/3)/(f*x+e)^3,x, algorithm="giac")

[Out]

integrate((b*x + a)^(4/3)/((d*x + c)^(4/3)*(f*x + e)^3), x)

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maple [F]  time = 0.24, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (b x +a \right )^{\frac {4}{3}}}{\left (d x +c \right )^{\frac {4}{3}} \left (f x +e \right )^{3}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^(4/3)/(d*x+c)^(4/3)/(f*x+e)^3,x)

[Out]

int((b*x+a)^(4/3)/(d*x+c)^(4/3)/(f*x+e)^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (b x + a\right )}^{\frac {4}{3}}}{{\left (d x + c\right )}^{\frac {4}{3}} {\left (f x + e\right )}^{3}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(4/3)/(d*x+c)^(4/3)/(f*x+e)^3,x, algorithm="maxima")

[Out]

integrate((b*x + a)^(4/3)/((d*x + c)^(4/3)*(f*x + e)^3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,x\right )}^{4/3}}{{\left (e+f\,x\right )}^3\,{\left (c+d\,x\right )}^{4/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^(4/3)/((e + f*x)^3*(c + d*x)^(4/3)),x)

[Out]

int((a + b*x)^(4/3)/((e + f*x)^3*(c + d*x)^(4/3)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**(4/3)/(d*x+c)**(4/3)/(f*x+e)**3,x)

[Out]

Timed out

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